Growing Faster than

the Speed of Light?

Nino's biography

Nino’s "hi!" video

Howard 's intro to V838 Mon

Howard's webpage

 

With Nino Panagia & Howard Bond

Howard Bond

In January 2002 a dull star in an obscure constellation suddenly became 600,000 times more luminous than our Sun, temporarily making it the brightest star in our galaxy.  

The star is called V838 Monocerotis (V 838 Mon) and is 20,000 light-years from Earth - about a fifth of the diameter of the Milky Way.

 

As well as getting a lot brighter, the star also illuminated surrounding shells of gas and dust.  These are arranged around the star like a Russian doll, one inside another. Each shell has been thrown out into space at a different time over millions of years. They only become visible when the light from the brightening star reaches them.  

As we knew how far away the star was, we were able to work out how far away the shells were from the star. But as we watched the object grow, we worked out that it appeared to be doing something impossible - expanding faster than the speed of light!

Your challenge is to use mathematics to find out what was is really going on

First lets think about how the light got to us from V838 Mon.

Some of the light came straight towards us.      Some of the light went away from us and was then reflected back towards us by the dust and gas behind the star.  Some of the light went at other angles and was reflected by the shells towards us.

Because the light took different routes to reach us, it arrived at different times.  The light that came directly towards us reached us first because it had taken the shortest route.  This was followed by the light that had gone in other directions. The scale of V838 Mon is so huge that light that went sideways reached us  months after the direct light did.

Task 1: measuring the light routes:

If we look at an image of V838 Mon 9 months after the star brightened, how much further will the light that has gone sideways have traveled to get to us than the light that came directly and arrived 9 months before?

You’ll need to know that the speed of light is

 5.913 x 1012 miles per year or 9.461 x 1012 kilometers per year

 For help and the answer click here.

 The different routes and arrival times of light explain why the image of V838 Mon started off small and appeared to get bigger as time went on. We call this effect a "light echo".

What puzzled us was how  how quickly the light echo increased in size.  

Task 2 (Part a): How fast does V838 Mon appear to be expanding?

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Scale Picture


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May 2002


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Sept 2002


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Oct 2002

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Dec 2002

Use the images above and our recommended program 'ImageJ' to measure the radius  of the first light echo (May 20th 2002).  You will need to measure in light years. Use the ‘Scale Picture’ on the left to set a scale for each picture (the top bar on the bottom left hand side).

Now, using the dates of the subsequent images predict what the maximum size of each echo should have been.  For example, if you find the first echo to have a radius of 3 light years, then the second echo, being 4 months later (May – September), should have a radius no larger than 3⅓ light years.

Now measure the size of each subsequent light echo and compare this to your predicted maximums.  What do you find?

 For help with this click here.

 To check your answers click here.

You can now see how we found that the star appeared to be expanding faster than the speed of light. But as you know, nothing can go faster than light. So why did this appear to be happening?

Task 2 (Part b): Use geometry to find out why V838 Mon appears to expand quicker than the speed of light

The structure of V838 Mon is very complicated.  We have light leaving in all directions being reflected in many directions by lots of layers of dust & gas.  We also have other light sources, mainly stars, also illuminating V838 Mon.

We’ll begin by creating a model of what we think is happening as the light leaves V838 Mon.  To make things easy we will make three simplifications.

1. There is just one layer of dust between the star and us and it is completely flat like a pane of glass.  It its also perpendicular to the line directly between us and the V838 Mon

2. V838 Mon is a point source of light and only ‘erupted’ once

3. Hubble collected images regularly in equal time intervals

You’ll also need to use your knowledge of geometry & Pythagoras.

Let us talk you through visualising the geometry of the problem with this PowerPoint show

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Geometrically the red lines must be bigger than the blue lines because the blue lines are the shortest distance between each consecutive circle and the red lines are not. 

Mathematically, we can now find out how much larger the red lines are than the blue lines by using Pythagoras’ Theorem.

 (Click here for a good explanation of Pythagoras’ Theorem, or alternatively type “Pythagoras Theorem” into Google to find your own explanations).

We’ll assume, for simplicity, that the images were taken a month apart.  This means that the distance between consecutive circles is 1 “light-month”.

We’ll also assume that the base length, the time it takes the direct light to reach the dust layer is 3 light-months.

To help illustrate things take a look at this PowerPoint Show.

Below are the images from the Show

In images B – E the letter ‘x’ refers to the unknown distance of the whole of the left hand side of the triangles and the letter ‘y’ refers to the unknown distance of each red line.

Click on them to enlarge and/or download.

     

A                                             B                                 C                                 D                                 E

In each image we’re finding the difference in length between the red line and the blue line.  This means finding the length of the red line and then subtracting the length of the blue line, which is always 1, from this.

For image A we can use simple Pythagoras.

 For help with this click here.

Images B – E are more complicated.  To find the length of each red line, labeled y, find the height of the triangle, labeled x, and then subtract the height of the previous triangle.

 For help with this click here.

 To check your answers click here.

Will the apparent expansion of V838 Mon ever be the same as the actual expansion?

So, we’ve seen that V838 Mon did appear to expand faster than the speed of light, we’ve also seen why this happened and we’ve even created and analysed a mathematical model of the light echo phenomena.

WELL DONE!